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7-x^2=8x
We move all terms to the left:
7-x^2-(8x)=0
We add all the numbers together, and all the variables
-1x^2-8x+7=0
a = -1; b = -8; c = +7;
Δ = b2-4ac
Δ = -82-4·(-1)·7
Δ = 92
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{92}=\sqrt{4*23}=\sqrt{4}*\sqrt{23}=2\sqrt{23}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-2\sqrt{23}}{2*-1}=\frac{8-2\sqrt{23}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+2\sqrt{23}}{2*-1}=\frac{8+2\sqrt{23}}{-2} $
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